y^2-12y+36y^2=0

Solution for y^2-12y+36y^2=0 equation:

y^2-12y+36y^2=0

We add all the numbers together, and all the variables

37y^2-12y=0

a = 37; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·37·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*37}=\frac{0}{74}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*37}=\frac{24}{74}
=12/37
$